MC.KJ

Home Archives
2019-02-17

java

递归

1
2
3
4
5
6
7
8
9
10
11
12
13
14
public class TestDemo {  
public static void main(String[] args) {
System.out.println(sum(100));
}

public static int sum(int num){
if(num == 1){
return 1;
}
return num + sum(num-1);

}

}

  • 终止条件
  • 递归一下次参数
  • 返回递归函数
Share
Newer
HTTP状态码
Older
hexo+github搭建博客以及主题更换

Archives

  • March 2020
  • February 2020
  • November 2019
  • October 2019
  • August 2019
  • February 2019

Recent Posts

  • markdown方式绘图
  • codeReview
  • 高可用散记
  • 负载均衡散记
  • Selenium Grid容器化-分布式测试
© 2020 MC.KJ
Powered by Hexo
Home Archives